(x^2 + 3x - 2)(x + 3)

Discussion in 'The Spam Zone' started by Master of the Onyx Flame, Sep 15, 2009.

  1. Master of the Onyx Flame Hollow Bastion Committee

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    i think i am getting the hang of this. this is correct right?
    x^3 + 6x^2 + 7x - 6
     
  2. the muffin man Banned

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    With a quick glance I think you're correct.
     
  3. Master of the Onyx Flame Hollow Bastion Committee

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    well, i multiplied everything in the left set by x. then by 3. and added the results all toghther...
    thanks again
     
  4. Inasuma "pumpkin"

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    (x^2 + 3x - 2)(x + 3)

    x^3 + 3x^2 + 3x^2 + 9x - 2x - 6

    x^3 + 6x^2 + 7x - 6

    yep.
     
  5. the muffin man Banned

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    Hey dude, do you know the "Horner's" system?
     
  6. Inasuma "pumpkin"

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    Hmm I don't think so. Sounds familiar though?
     
  7. the muffin man Banned

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    It's a method that what it practically does is the reverse of what we just did.
    Meaning that x^3 + 6x^2 + 7x - 6 you can "deflate" thiis polynimial into a polyonimial with a smaller power. This polyonimial is 3rd power, with horner's method we can divide it in a polinimial with a power smaller by 1. Like this: (x^2 + 3x - 2)(x + 3)
    I don't think you understood what I said because I said it complicated and might have said something wrong in there, but I was just checking if you know it.
     
  8. Inasuma "pumpkin"

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    Oh, yes, I do. This would involve synthetic/long division I think.

    Going from a 3rd power to a 2nd power, or if it's a 5th power, down to a 4th power or lower. If the term (x+b) at the end is over 1, long division is required. If it's just 1 or 0, it can be synthetically simplified. Something like that?
     
  9. the muffin man Banned

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    Yeah, yeah that's it. Good.
     
  10. Inasuma "pumpkin"

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    I haven't used that method in a couple semesters so it's a bit foggy. I think I can still do it though if I tried hard enough. oh lulz