Yeah, this is where it sometimes gets complicated. You're right. Just remember when you're squaring a whole equation that it's not squaring the individual number or variable, but you're just re-writing the equation that many times. (x+1)^2 = (x+1)(x+1) Then you just solve and simplify using FOIL(First Outer Inner Last). Then combine like terms and you're done. Once you get the hang of it, it becomes second nature. **EDIT** Is the equation you posted what you want us to solve? Because the left side is the simplified version of the right side. Either way, the answer is 2x(2) + 4x + 2, if that's what you wanted us to do.
sHe wants us to prove this probably. I've done this a million times in school, and I don't want to make them a million and one :P
(X+1)^2=X^2+2x+1 X^2+x+x+1=X^2+2x+1 X^2+2x+1=X^2+2x+1 The original equation is an identity equation. There are infinitely many solutions.
ugh guessing its A level maths ? i got simple one's for now :) BUT i have a prediction i think the answer is 7!
(x+1)^2 = X^2 + 2x +1 (x+1)(x+1) = X^2 + 2x + 1 X^2 + X + X + 1 = X^2 + 2x + 1 X^2 + 2x + 1 = X^2 + 2x + 1 My head hurts... I haven't done math in almost a year. Mainly Algebra... @_@
For those that don't know the correct notation for an index would be (for example) x^2 which means "x to the power of 2". Putting a number or something in brackets implies multiplication and will just cause confusion.
Yeah that's why I asked. If she means "-4 to the power of 7x" then it the answer is: F(x)=[[2^(14X-1)]/7ln(2)] - 5x