http://porn.corn [A landscaper has two gardens: one is a square and the other is a rectangle. The width of the rectangular garden is 5 yards less than a side of the square one, and the length of the rectangular garden is 3 yards more than a side of the square garden. If the sum of the areas of both gardens is 165 square yards, find the measure of a side of the square garden.]
Am i doing something wrong? 10 x 10 = 100 10-5 = 5 10+3 = 13 5 x 13 = 65 100+65 = 165 Note: Only halfway through Alg. 2/trig so if it's something i don't know or don't remember, i apologize.
Ten is the rejected value. You're left towards the end with this: (x-9)(x+10) = 0 Solving, you get the following: x = 9 | x = -10 So you use the nine. Oh, have you done quadratics yet? You need that to solve this problem.
I would just like to clarify that 10 was in fact the right answer and I nearly pissed myself in Math Class today for not believing Saint Nick.
