A Chem Problem? =O

Discussion in 'The Spam Zone' started by Advent, Sep 30, 2008.

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  1. Toshi Banned

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    I g2g now, so maybe I'll look through the problem more carefully tomorrow (if I will be able to) and if you don't mind.
     
  2. Advent 【DRAGON BALLSY】

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    Haha sure. It's not due 'till Thursday.
     
  3. Explode Who?!

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    I'm pretty sure that the answer won't make sense unless you balance the equation. I'm going to fumble around with the equation and try to make sense of it, but I could be totally wrong.

    Both sides of the equation must have the same number of grams. 11.19 (CO2) + 9.16 (H2O) = 20.35g. Therefore, there must be 20.35g on each side of the equation. So, if there are 8.14g of a substance and X grams of O2 on the left side, then X must equal 12.21g.

    Alright, well one mole of CO2 is about 44 grams, so 11.19g is roughly .25 moles, and one mole of H2O is about 18g, so 9.16g is roughly .5 moles. Finally, one mole of O2 is 32g, so 12.21g of O2 is .375 moles. Let's multiply this by four to get simpler numbers:

    X + (1.5)O2 -----> CO2 + (2)H2O

    Now, X must consist of one carbon, four hydrogens and one oxygen in order to keep the equation balanced:

    CH4O + (1.5)O2 -------> CO2 + (2)H2O

    But I don't think you can have decimals in an empirical formula, so let's multiply everything by two:

    (2)CH4O + (3)O2 -------> (2)CO2 + (4)H2O

    I have no idea if this is right, but the logic seems okay.
     
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