How Many Xehanort Fights do you Think There will be in KH3?

I'm thinking at least around 25, keeping in mind that there will probably be multiple forms.
In fact, we may be looking at over 20 Xehanort fights in one game here.

 

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I'd say 50. No, I'm not joking, I'm serious. You'll probably encounter them in the Disney worlds and then fight them again later, like Demyx. And then they'll have multiple forms.

 

Too soon to say?
I would say 50 is an absurd number considering there are only 13 of them, and end-game bosses are so far the only ones with multiple forms that could count as multiple fights that I can think of right now.
I would say around 20-25 would be a good estimate if I had to guess, but that's not my official guess because as I said it's too soon to say.

 

I figured there'd be a Demyx type fight, but now that I think about it, there'll probably be a Xehanort fight in each Disney Princess world, plus a gauntlet around the end (Some Xehanort might die before the end, but there'll probably be at least six left) and then there'll probably be like four forms for the final Xehanort... mayeb two for Ansem and Xemnas as well.
That's a lot of Xehanort.

 

S

Sure is.

 

I'm not sure, honestly. My guess would be around the 15 or so mark.

Anything more than that would be optional bosses (who? idk), Heartless/Nobody bosses (they didn't just disappear) and maybe another round with Maleficent. I really don't like how she got shafted in Re:Coded and KH 3D.

 

erm... might want to read the topic title...

 

Probably around 26. Fighting each one once seperately. Fighting all of them at the end together. And maybe a couple as data/rematch fights so 30ish?
Just a guess though

 

Well, she's not exactly the main antagonist, and she's not the focus anymore like she was in KH1. That's why a thread like this exists. Xehanort is the main antagonist, so he will naturally get more attention than a Disney villain whose only real purpose was to get the ball rolling earlier in the series and make the Disney worlds seem just as significant as everything else. She wasn't shafted, she got the appropriate amount of attention for a villain as important, or not important, as she is.

 

No idea, I guess around 20.

 

Im gonna go out on a limb here and say As many worlds there are, thats how many Xeranort fights there will be. then add 5 to that total considering im sure there will be around 5-7 fights in what im guessing the final world will be "the world that never was" again. Every world boss will be a form of Xeranort. it makes sense to me to have a form of him being a boss in every world. But i guess only time will tell. but in total im guessing around 20 or so. possible 13 worlds, then 5-7 Xeranorts in the final world.

But lemme follow up with a question, is this assuming youll only play as Sora, or do you think Theyll do like DDD where u play as Sora and Riku or Kairi or whoever else? because if thats the case you could easily double that number.

 

Let's say that you can play as even Yen Sid. Lol

 

lol id be okay with that :P

 

My guess would be around 36 because we already know that Xemnas has a few forms since we fought them before. And if you add the possibility there might be an arena where you can battle extra boss and things like in the past KH games. If my theory is right it would be impossible to say how many Xehanort fights there are really because there would be no limit to the amount of times you battle him in the arena.

 

I'm gonna have to agree with Oda on this one, 36 seems about right considering that in past KH games, we battle alot of the bosses at least twice, plus the multiple forms for the final battle, that would add up to at least 30-36 battles. And, if they bring back the Mirage Arena, it'd be impossible to estimate how many Xehanort battles there would be in the Arena, and it'd be impossible to estimate how many times an individual would re-play the Arena matches

 

I'm going to get sick of hearing Xehanort's name.....